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-5c^-9c^2=0
We add all the numbers together, and all the variables
-9c^2-5c=0
a = -9; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-9)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-9}=\frac{0}{-18} =0 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-9}=\frac{10}{-18} =-5/9 $
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